I was fiddling around with a deck of cards today, and it occurred to me that it might be possible to emulate the math of Moldvay's table for stocking a dungeon on page B52 of the his Basic Rulebook with a deck of cards. He has us rolling 1d6 to determine the contents of a room:
1-2 Monster
3 Trap
4 Special
5-6 Empty
A second roll determines whether or not there is Treasure:
Monster: 1-3 Yes; 5-6 No
Trap: 1-2 Yes; 3-6 No
Empty: 1 Yes; 2-6 No
If you include a pair of Jokers, a deck has 54 cards, which is dividable by 6. That means we can assign each of the four outcomes of our Room Contents Table to 9 cards. This comes out to 18 cards for Monsters, 9 cards for Traps, 9 cards for Specials, and 18 cards for Empty Rooms. With these groups, 9 of the Monster, 3 of the Traps, and 1 of the Empty Rooms would indicate a Treasure.
A deck of cards could thus be divvied up as follows:
2D = Empty with Treasure
3D-5D = Trap with Treasure
6D-AD = Monster with Treasure
2C-5C = Empty
6C-AC = Monster
2H-5H = Empty
6H-AH = Special
2S-8S = Empty
9S-AS = Trap
Jokers = Could indicate an Empty Room or Placed Encounter
Of course, all of this assumes that your dungeon has multiples of 54 rooms... but being a fan of the megadungeon, this is no real issue for me.
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