Tuesday, February 20, 2024

Stocking a Moldvay Dungeon with a Deck of Cards

I was fiddling around with a deck of cards today, and it occurred to me that it might be possible to emulate the math of Moldvay's table for stocking a dungeon on page B52 of the his Basic Rulebook with a deck of cards. He has us rolling 1d6 to determine the contents of a room:

1-2 Monster 

3 Trap

4 Special

5-6 Empty

A second roll determines whether or not there is Treasure: 

Monster: 1-3 Yes; 5-6 No

Trap: 1-2 Yes; 3-6 No

Empty: 1 Yes; 2-6 No

If you include a pair of Jokers, a deck has 54 cards, which is dividable by 6. That means we can assign each of the four outcomes of our Room Contents Table to 9 cards. This comes out to 18 cards for Monsters, 9 cards for Traps, 9 cards for Specials, and 18 cards for Empty Rooms. With these groups, 9 of the Monster, 3 of the Traps, and 1 of the Empty Rooms would indicate a Treasure.

A deck of cards could thus be divvied up as follows:

2D = Empty with Treasure

3D-5D = Trap with Treasure

6D-AD = Monster with Treasure

2C-5C = Empty

6C-AC = Monster

2H-5H = Empty

6H-AH = Special

2S-8S = Empty

9S-AS = Trap

Jokers = Could indicate an Empty Room or Placed Encounter

Of course, all of this assumes that your dungeon has multiples of 54 rooms... but being a fan of the megadungeon, this is no real issue for me. 

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